I had a bunch of files named like;
IMG_2345 2.JPG
I wanted to remove the space and the 2 so that it would become like:
IMG_2345.JPG
How to do this in a one liner?
Can't use usual for file in `ls *\ 2.JPG`;do mv $file etc, as it will
treat the space as a newline (and quoting $file to "$file" won't do it
either.
There is a convenient way of doing this with 'read', as well as using built-in string replacement
ls *\ 2.JPG | while read line;do mv "$line" "${line/\ 2/}";done
Substring Replacement
${string/substring/replacement}
Replace first match of $substring with $replacement.
${string//substring/replacement}
Replace all matches of $substring with $replacement.
http://www.linuxtopia.org/online_books/advanced_bash_scripting_guide/string-manipulation.html
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